问题补充:
单选题曲线y=sinx+e x在点(0,1)处的切线方程是A.x-3y+3=0B.x-2y+2=0C.2x-y+1=0D.3x-y+1=0
答案:
C解析解:∵f(x)=ex+sinx=∴f′(x)=ex+cosx,∴在x=0处的切线斜率k=f′(0)=1+1=2,∴f(0)=1+0=1,∴f(x)=ex+sinx在x=0处的切线方程为:y-1=2x,∴y=2x+1,故
时间:2020-10-08 13:53:02
单选题曲线y=sinx+e x在点(0,1)处的切线方程是A.x-3y+3=0B.x-2y+2=0C.2x-y+1=0D.3x-y+1=0
C解析解:∵f(x)=ex+sinx=∴f′(x)=ex+cosx,∴在x=0处的切线斜率k=f′(0)=1+1=2,∴f(0)=1+0=1,∴f(x)=ex+sinx在x=0处的切线方程为:y-1=2x,∴y=2x+1,故
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