GPS纠偏算法，适用于google,高德体系的地图,精确度还比较高。我试了一下比高德本身的纠偏还精确点。
/*** gps纠偏算法，适用于google,高德体系的地图* @author Administrator*/public class GpsCorrect {final static double pi = 3.14159265358979324;final static double a = 6378245.0;final static double ee = 0.00669342162296594323;public static void transform(double wgLat, double wgLon, double[] latlng) {if (outOfChina(wgLat, wgLon)) {latlng[0] = wgLat;latlng[1] = wgLon;return;}double dLat = transformLat(wgLon - 105.0, wgLat - 35.0);double dLon = transformLon(wgLon - 105.0, wgLat - 35.0);double radLat = wgLat / 180.0 * pi;double magic = Math.sin(radLat);magic = 1 - ee * magic * magic;double sqrtMagic = Math.sqrt(magic);dLat = (dLat * 180.0) / ((a * (1 - ee)) / (magic * sqrtMagic) * pi);dLon = (dLon * 180.0) / (a / sqrtMagic * Math.cos(radLat) * pi);latlng[0] = wgLat + dLat;latlng[1] = wgLon + dLon;}private static boolean outOfChina(double lat, double lon) {if (lon < 72.004 || lon > 137.8347)return true;if (lat < 0.8293 || lat > 55.8271)return true;return false;}private static double transformLat(double x, double y) {double ret = -100.0 + 2.0 * x + 3.0 * y + 0.2 * y * y + 0.1 * x * y + 0.2 * Math.sqrt(Math.abs(x));ret += (20.0 * Math.sin(6.0 * x * pi) + 20.0 * Math.sin(2.0 * x * pi)) * 2.0 / 3.0;ret += (20.0 * Math.sin(y * pi) + 40.0 * Math.sin(y / 3.0 * pi)) * 2.0 / 3.0;ret += (160.0 * Math.sin(y / 12.0 * pi) + 320 * Math.sin(y * pi / 30.0)) * 2.0 / 3.0;return ret;}private static double transformLon(double x, double y) {double ret = 300.0 + x + 2.0 * y + 0.1 * x * x + 0.1 * x * y + 0.1 * Math.sqrt(Math.abs(x));ret += (20.0 * Math.sin(6.0 * x * pi) + 20.0 * Math.sin(2.0 * x * pi)) * 2.0 / 3.0;ret += (20.0 * Math.sin(x * pi) + 40.0 * Math.sin(x / 3.0 * pi)) * 2.0 / 3.0;ret += (150.0 * Math.sin(x / 12.0 * pi) + 300.0 * Math.sin(x / 30.0 * pi)) * 2.0 / 3.0;return ret;}}
源码下载地址：/detail/junfeng15/5945349
