/ch0104/09/
/*1.4编程基础之逻辑表达式与条件分支 09 判断能否被3,5,7整除/ch0104/09//yigezzchengxuyuan/article/details/86651658*/#include<iostream>using namespace std;int main(){int n;cin>>n;if( (n%3==0) && (n%5==0) && (n%7==0)){cout<<"3 5 7";return 0;}if( (n%3==0) && (n%5==0) ){cout<<"3 5";return 0;}if( (n%3==0) && (n%7==0) ){cout<<"3 7";return 0;}if( (n%5==0) && (n%7==0) ){cout<<"5 7";return 0;}if(n%3==0){cout<<"3";return 0;}if(n%5==0){cout<<"5";return 0;}if(n%7==0){cout<<"7";return 0;}cout<<"n";return 0;}