将它连接到仅有最大计数的第二个查询。每天最内部查询(对于给定用户)每天计数的一组行数。从那以后，下一个外部执行从该集合中选择MAX()来查找并获得一个代表最高日数的记录...因为它总是返回一行，并且加入到原始的numRequest表中它将是一个笛卡尔，但没有问题，因为它只有一条记录，无论如何你想要每个返回行的值。
select
id_re_usr,
year(time) as AYear,
DAYOFYEAR(time) as ADay,
DATE_FORMAT(time, "%m-%d-%y") as date,
count(*) as TotalPerDay,
HighestCount.Max1 as HighestOneDayCount
from
numrequest,
( select max( CountsByDate.DayCount ) Max1
from ( select count(*) as DayCount
from numrequests nr
where nr.id_re_usr = "u1"
group by date( nr.time )) CountsByDate
) HighestCount
where
id_re_usr = "u1"
group by
id_re_usr,
AYear,
ADay
order by
AYear,
ADay
