前提 后台代码抄过来的 侵删
保存一下方便以后使用
前台js
window.atob();
window.btoa()；
后台
import java.io.UnsupportedEncodingException;
import .URLDecoder;
import .URLEncoder;
import java.util.regex.Matcher;
import java.util.regex.Pattern;
import org.apache.log4j.Logger;
/**
@author zxy
@date 8月24日 上午11:20:16
@Description : 字符串加密类
*/
public class BtoAAtoB {
private static Logger log = Logger.getLogger(“BtoAAtoB.class”);
private static String base64hash = “ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/”;
public static boolean isMatcher(String inStr, String reg) {
Pattern pattern = pile(reg);
Matcher matcher = pattern.matcher(inStr);
if (matcher.matches()) {
return true;
}
return false;
}
/**
btoa method
@param inStr
@return
*/
public static String btoa(String inStr) {
if (inStr == null || isMatcher(inStr, “([^\u0000-\u00ff])”)) {
return null;
}
StringBuilder result = new StringBuilder();
int i = 0;
int mod = 0;
int ascii;
int prev = 0;
while (i < inStr.length()) {
ascii = inStr.charAt(i);
mod = i % 3;
switch (mod) {
case 0:
result.append(String.valueOf(base64hash.charAt(ascii >> 2)));
break;
case 1:
result.append(String.valueOf(base64hash.charAt((prev & 3) << 4 | (ascii >> 4))));
break;
case 2:
result.append(String.valueOf(base64hash.charAt((prev & 0x0f) << 2 | (ascii >> 6))));
result.append(String.valueOf(base64hash.charAt(ascii & 0x3f)));
break;
}
prev = ascii;
i++;
}
if (mod == 0) {
result.append(String.valueOf(base64hash.charAt((prev & 3) << 4)));
result.append("==");
} else if (mod == 1) {
result.append(String.valueOf(base64hash.charAt((prev & 0x0f) << 2)));
result.append("=");
}
return result.toString();
}
/**
atob method 逆转encode的思路即可
@param inStr
@return
*/
public static String atob(String inStr) {
if (inStr == null)
return null;
inStr = inStr.replaceAll("\s|=", “”);
StringBuilder result = new StringBuilder();
int cur;
int prev = -1;
int mod;
int i = 0;
while (i < inStr.length()) {
cur = base64hash.indexOf(inStr.charAt(i));
mod = i % 4;
switch (mod) {
case 0:
break;
case 1:
result.append(String.valueOf((char) (prev << 2 | cur >> 4)));
break;
case 2:
result.append(String.valueOf((char) ((prev & 0x0f) << 4 | cur >> 2)));break;case 3:result.append(String.valueOf((char) ((prev & 3) << 6 | cur)));break;}prev = cur;i++;
}
return result.toString();
}
/**
加密字符串@return
*/
public static String encryption(String str) {
String encode;
try {
encode = URLEncoder.encode(str,“utf-8”);
encode=encode.replaceAll("\+", “%20”);//URLEncoder.encode 会将空格解释为+号
String btoa = BtoAAtoB.btoa(encode);
return btoa;
} catch (UnsupportedEncodingException e) {
log.info(“btoa加密函数出现错误。”);
}
return str;
}
/**
解密字符串@return
*/
public static String decrypt(String str) {
String atob = BtoAAtoB.atob(str);
try {
String decode = URLDecoder.decode(atob, “utf-8”);
return decode;
} catch (UnsupportedEncodingException e) {
log.info(“atob加密函数出现错误。”);
}
return str;
}
}
————————————————
版权声明：本文为CSDN博主「z793397795」的原创文章，遵循CC 4.0 BY-SA版权协议，转载请附上原文出处链接及本声明。
原文链接：/z793397795/article/details/108196422
