js获取多个select下拉框选中的值
var electronicIds = [];
$("select[name='electronicId']").each(function(j,item){
electronicIds.push(document.getElementsByTagName("select")[j].value);
});
例子:
var row= "<div class='table-style'>"
+"<div class='row' id='addRow'>"
+"<div class='col-sm-1 col-xs-4'><span>*</span>电子券:</div>"
+"<div class='col-sm-3 col-xs-8 div-select'>"
+"<select class='form-control dselect' name='electronicId' id='select'>"
+"<option value='' label='' title=''>---请选择---</option>"
+"<#list elist as list>"
+"<option value='${(list.id)!}' label='${(list.typeSign)!}' title='${(list.reduceMoney)!}'>${(list.title)!}</option>"
+"</#list>"
+"</select>"
+"</div>"
+"<div class='col-sm-4 col-xs-12'><button class='btn btn-sm btn-danger ' οnclick='delRow(this)'>删除</button></div>"
+"</div>"
+"</div>";
$("#baseinfo2").append(row);