数据库|mysql教程
sql查询,连续记录
数据库-mysql教程
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有这样一个需求：需要查询出某个客户某一年那些天是有连续办理过业务,本文给予sql实现语句并测试，感兴趣的朋友可以了解下
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需求说明：
需要查询出某个客户某一年那些天是有连续办理过业务
实现SQL如下：
创建表：
代码如下:
create table test_num
(tyear number,
tdate date);
测试数据：
insert into test_num
select ,trunc(sysdate)-1 from dual union all
select ,trunc(sysdate)-002 from dual union all
select ,trunc(sysdate)-003 from dual union all
select ,trunc(sysdate)-004 from dual union all
select ,trunc(sysdate)-005 from dual union all
select ,trunc(sysdate)-007 from dual union all
select ,trunc(sysdate)-008 from dual union all
select ,trunc(sysdate)-009 from dual union all
select ,trunc(sysdate)-120 from dual union all
select ,trunc(sysdate)-121 from dual union all
select ,trunc(sysdate)-122 from dual union all
select ,trunc(sysdate)-124 from dual union all
select ,trunc(sysdate)-125 from dual union all
select ,trunc(sysdate)-127 from dual union all
select ,trunc(sysdate)-099 from dual union all
select ,trunc(sysdate)-100 from dual union all
select ,trunc(sysdate)-101 from dual union all
select ,trunc(sysdate)-102 from dual union all
select ,trunc(sysdate)-104 from dual union all
select ,trunc(sysdate)-105 from dual;
写SQL:
代码如下:
SELECT TYEAR, MIN(TDATE) AS STARTDATE, MAX(TDATE), COUNT(TYEAR) AS ENDNUM
FROM (SELECT A.*, A.TDATE – ROWNUM AS GNUM
FROM (SELECT * FROM TEST_NUM ORDER BY TYEAR, TDATE) A)
GROUP BY TYEAR, GNUM
ORDER BY TYEAR, MIN(TDATE)
