后端开发|php教程
php,mysql,while,循环
后端开发-php教程
php的mysql查询语句可不可以这样用呢？
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; }$query = "SELECT name FROM bank WHERE area LIKE aaa\";$result = mysql_query($query) or die(mysql_error());while($row = mysql_fetch_array($result)) { $http = $row[http]; $task_query = "SELECT * FROM task WHERE link LIKE\%$http%\"; $task_result = mysql_query($task_query) or die(mysql_error()); while($task = mysql_fetch_array($task_result)); echo $task[high].
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php的mysql查询语句可不可以这样用呢？
; }$query = "SELECT name FROM bank WHERE area LIKE aaa\";$result = mysql_query($query) or die(mysql_error());while($row = mysql_fetch_array($result)) { $http = $row[http]; $task_query = "SELECT * FROM task WHERE link LIKE\%$http%\"; $task_result = mysql_query($task_query) or die(mysql_error()); while($task = mysql_fetch_array($task_result)); echo $task[high].
SELECT *FROM task JOIN (SELECT http AS zhttp FROM bank WHERE area LIKE aaa) AS ZON task.link LIKE CONCAT(\%, Z.zhttp, \%)
SELECT * FROM bank LEFT JOIN task ON task.link LIKE concat(\%, bank.http, \%) WHERE bank.area = aaa
我觉得你可能需要JOIN….
select task.high from task left join bank on task.link like concat(\%, bank.http. \%) where bank.area like aaa
你在$task_query = "SELECT * FROM task WHERE link=\%$http%\";这里应该是希望得到模糊匹配的效果，怎么能用=呢？
